Class 8th Mathematics MCQ
Chapter 9: Algebraic Expressions and Identities Part 2
Q70. The side of a cube is 2a. Find the volume of the cube.
1. 8
2. 8a
3. 4a
4. 2a
Ans: 2. 8a
Solution:
Volume of the cube = 2a × 2a × 2a = 8a
Q71. What should be added to 9y -7xyz + 8z – xy to get 3xy + 8zy – 2xyz + z we get:
1. -9y + 4xy + 8zy + 5xyz + z – 8z
2. 9y + 4xy + 8yz + 5xyz + z + 8z
3. 9y + 4xy + 8zy + 5xyz + z – 8z
4. None of these
Ans: 1. -9y + 4xy + 8zy + 5xyz + z – 8z
Solution:
Subtracting 9y – 7xyz + 8z – xy from 3xy + 8zy – 2xyz + z , we ge
Q72. The value of x – 2yx + y when x = 1, y = 2 is:
1. 1
2. -1
3. 2
4. -2
Ans: 1. 1
Solution:
Value = (1) – 2(2)(1) + (2) = 1
Q73. Use suitable identity to evaluate 992.
1. 9801
2. 10199
3. 10201
4. 10001
Ans: 1. 9801
Q74. (a – b) is equal to:
1. a + b + 2ab
2. 2ab
3. a + b – 2ab
4. a + ba
Ans: 3. a + b – 2ab
Solution:
By algebraic identity,
(a + b) = a + b – 2ab
Q75. The value of (3x + 9x + 27x) ÷ 3x is:
1. x + 9 + 27x
2. 3x + 3x + 27x
3. 3x + 9x + 9
4. x + 3x + 9
Ans: 4. x + 3x + 9
Solution:
(3×2 + 9×2 + 27x)
=
3×3 + 9×2 + 27x
3x
=
3×3
3x +
9×2
3x +
27x
3x
= x2 + 3x + 9
Q76. Tick (✓ ) the correct answer:
(3q + 7p – 2r + 4) – (4p – 2q + 7r – 3) = ?
1. (p + 2q + 5r + 1)
2. (11p + q + 5r + 1)
3. (-3p – 5q + 9r – 7)
4. (3p + 5q – 9r +7)
Ans: 4. (3p + 5q – 9r +7)
Solution:
(3q + 7p – 2r + 4) – (4p – 2q + 7r – 3)
= 3q + 7p – 2r + 4 – 4p + 2q – 7r + 3
= 5q + 3p – 9r + 7
= 3p + 5q – 9r + 7
Q77. Which of the following is a binomial?
1. 3xy
2. 4l + 5m
3. 2x + 3y – 5
4. 4a – 7ab + 3b + 12
Ans: 2. 4l + 5m
Solution:
4l + 5m contains two terms.
Q78. Evaluate (199.5) using a suitable identity.
1. 400200.25
2. 39800.025
3. 39800.25
4. 39800
Ans: 3. 39800.25
Solution:
(199.5) = (200 – 0.5) and using (a – b) = a – 2ab + b = (200) – 2 × 200 × 0.5 + (0.5) = 40000 – 200 + 0.25 = 39800.25
Q79. The result of subtraction of 7x from 0 is:
1. 0
2. 7x
3. -7x
4. x
Ans: 3. -7x
Solution:
0 – 7x = -7x
Q80. Which of the following is not binomial:
1. M + n
2. Mn
3. M – n
4. M2 – n2
Ans: 2. Mn
Q81. Surbhi tries o make one of the first three identities from (x + a)(x + b) = x + (a + b)x + ab by replacing a and b both
by – c which identity did she obtain by this?
1. (a – b) = a – 2av + b
2. (a – b) = a – 2ab + b
3. a – b = (a + b)(a – b)
4. (x + a)(x + b) = x – (a + b) x + ab remains same
Ans: 2. (a – b) = a – 2ab + b
Solution:
(x + a)(x + b) = x + (a + b) x + ab
Replacing a and b both by – c, we get
(x – c)(x – c) = x + (-c -c) x + (-c) (-c)
Or, (x – c)2 = x – 2 cx + c
It is similar to
(a – b) = a – 2ab + b
Q82. Which of the following is a binomial?
1. 7 × a + a
2. 6a + 7b + 2c
3. 4a × 3b × 2c
4. 6 (a + b)
Ans: 4. 6 (a + b)
Solution:
Binomials are algebraic consisting of two unlike terms.
1. 7 × a + a = 7a + a = 8a (monomial)
2. 6a + 7b + 2c (trinomial)
3. 4a × 3b × 2c (monomial)
4. 6(a + b) = 6a + 6b (binomial)
Q83. What is the formulae for (x – y) ?
1. x + 2xy + y
2. x – 2xy + y
3. x – 2xy – y
4. x – y
Ans: 2. x – 2xy + y
Q84. The product of 4x and 0 is:
1. 4
2. 0
3. 4x
4. None of the above
Ans: 2. 0
Solution:
Any value multiplied by zero is zero.
Q85. ‘2’ is common factor of the expressions
1. 12a b, 15ab
2. 5xy, 10x
3. 10x , -18x , 14x
4. 33y, -22z
Ans: 3. 10x , -18x , 14x
Q86. Factorised form of p – 17p – 38 is:
1. (p – 19)(p + 2)
2. (p – 19)(p – 2)
3. (p + 19)(p + 2)
4. (p + 19)(p – 2)
Ans: 1. (p – 19)(p + 2)
Solution:
We have,
p – 17p – 38
= p – 19p + 2p – 38
= p(p – 19) + 2(p – 19)
= (p – 19)(p + 2)
Q87. The value of x – 2x + 1 when x = 1 is:
1. 1
2. 2
3. -2
4. 0
Ans: 4. 0
Solution:
Value = (1) – 2(1) + 1 = 0
Q88. If a+b + c = 10 and a2 + b2 + c2 = 36 then ab+bc + ca = ________
1. 136
2. 64
3. 32
4. 68
Ans: 3. 32
Q89. Which of the following is a monomial?
1. 4x
2. a + 6
3. a + 6 + c
4. a + b + c + d
Ans: 1. 4x
Solution:
4x contains only one term.
Q90. What do you get when you subtract -3xy from 5xy?
1. 3xy
2. 5xy
3. 8xy
4. xy
Ans: 3. 8xy
Solution:
5xy – (-3xy) = 5xy + 3xy = 8xy
Q91. The product of 3xy z and 4x is:
1. 12x yz
2. 12xy
3. 12xyz
4. 12x y z
Ans: 4. 12x y z
Solution:
The product of 3xy z and 4x is:
⇒ (3xy z) (4x)
⇒ 3.x.y .z.4.x
⇒ 12x y z
Q92. If the product of two numbers is 10 and the sum is 7, then the larger of the two numbers is:
1. -2
2. 5
3. 2
4. None of these
Ans: 2. 5
Q93. (3x – 5y) – (5x – 2y) + (2x + 3y)
1. -3(3x – 5y)(2x – 5y)(2x + 3y)
2. 3(3x – 5y)(5x – 2y)(2x + 3y)
3. (3x – 5y)(2y – 5x)(2x + 3y)
4. (3x – 5y)(5x – 2y)(2x + 3y)
Ans: 1. -3(3x – 5y)(2x – 5y)(2x + 3y)
Q94. What is the volume of a cube having side (3ab)cm :
1. (27a b )cm
2. (9ab)cm
3. (27ab)cm
4. (9a b )cm
Ans: 1. (27a b )cm
Solution:
The volume of a cube having side 3ab = (3ab) × (3ab) × (3ab) = 3 × 3 × 3 (ab) (ab) (ab) = (27a b )cm
Q95. The product of 7x and -12x is:
1. 84x
2. -84x
3. x
4. -x
Ans: 2. -84x
Solution:
(7x)(-12x) = -84x
Q96. The equality b + 5 > 9b + 12 us satisfied if:
1. b > 8 (or) b < 0
2. b = 10 (or) b = –1
3. b > 9 (or) b < 0
4. b > 9 (or) b < 1
Ans: 3. b > 9 (or) b < 0
Q97. The number of like terms in abc, – abc, – bca, acb, bac,
1
2 12cab is:
1. 6
2. 4
3. 3
4. 2
Ans: 1. 6
Solution:
All are like terms
Q98. What are added together to form an expression?
1. Factors
2. Terms
3. Coefficients
4. Variables
Ans: 2. Terms
Solution:
The correct option (B) because expressions are formed by adding terms together.
Q99. Product of the following monomials 4p, -7q , -7pq is:
1. 196 p q
2. 196 pq
3. -196 p q
4. 196 p q
Ans: 1. 196 p q
Solution:
Required Product = 4p × (-7q ) × (-7pq)
= 4 × (-7) × (-7)p × q × pq
= 196p q
Q100. Simplify 7pq(q + r) – 8s(p + 2q) + 2r(pq + rs) + 4ps:
1. 7pq + 9pqr + 4ps + 16qs + 2r s
2. 7pq + 5pqr – 4ps + 16qs + 2r s
3. 7pq + 9pqr – 4ps – 16qs + 2r s
4. 7pq – 5pqr + 4ps – 16qs + 2r s
Ans: 3. 7pq + 9pqr – 4ps – 16qs + 2r s
Solution:
7pq(q + r) – 8s(p + 2q) + 2r(pq + rs) + 4ps = 7pq (q) + 7pq(r) – 8s(p)-
8s(2q) + 2r(pq) + 2r(rs) + 4ps
7pq + 7pq(r) – 8ps – 16qs + 2pqr + 2r s + 4ps 7pq + 9pqr – 8ps – 4ps – 16qs + 2r
Q101. Which of the following expression is trinomial:
1. xyz
2. xy + z
3. x + y + z
4. x + yz
Ans: 3. x + y + z
Q102. The common factor of 3ab and 2cd is:
1. 1
2. -1
3. a
4. c
Ans: 1. 1
Solution:
We have, monomials 3ab and 2cd Now, 3ab = 3 × a × b and 2cd = 2 × c × d Observing the monomials, we see that, there is no common
factor (neither numerical nor literal) between them except 1.
Q103. The value of (x – y)(x + y) + (y – z)(y + z) + (z – x)(z + x) is:
1. 0
2. x + y + z
3. x + y + z
4. xy + yz + zx
Ans: 1. 0
Solution:
(x – y)(x + y) + (y – z)(y + z) + (z – x)(z + x)
= x – y + y – z + z – x
[By algebraic identity: a – b = (a + b)(a – b)]
= 0
Q104. The like terms of the following are:
1. 2x , 9x
2. y , xy
3. xy, 9a
4. y , 9x
Ans: 1. 2x , 9x
Q105. (x – y)(x + y) + (y – z)(y + z) + (z – x)(z + x) is equal to:
1. 0
2. x + y + z
3. xy + yz + zx
4. x + y + z
Ans: 1. 0
Solution:
(x – y)(x + y) + (y – z)(y + z) + (z – x)(z + x) = x – y + y – z + z – x = 0
Q106. The factorised form of 3x – 24 is:
1. 3x × 24
2. 3(x – 8)
3. 24(x – 3)
4. 3(x – 12)
Ans: 2. 3(x – 8)
Solution:
We have,
3x – 24 = 3 × x – 3 × 8 = 3(x – 8)
[taking 3 as common]
Q107. The result of subtraction of 3x from -4x is:
1. -7x
2. 7x
3. x
4. -x
Ans: 1. -7x
Solution:
-4x – 3x = -7x
Q108. The value of (a + b) + (a – b) is:
1. 2a + 2b
2. 2a – 2b
3. 2a + 2b
4. 2a – 2b
Ans: 3. 2a + 2b
Solution:
We have,
(a+ b) + (a – b) = (a + b + 2ab) + (a + b – 2ab)
= (a + a ) + (b + b ) + (2ab – 2ab)
= 2a + 2b
Q109. Multiplication of pq + qr + rp and ‘zero’ is:
1. pq + qr
2. pq + rp
3. pq + qr + nrp
4. 0
Ans: 4. 0
Q110. Tick (✓ ) the correct answer:
If x −
1
x = 6, then x2 +
1
x2 = ?
1. 36
2. 38
3. 32
4. 36
1
36
Ans: 2. 36
Solution:
x −
1
x = 6,
Squaring on both sides
x −
1
x
2 = (6)2
⇒ x2 +
1
x2 − 2 = 36
⇒ x2 +
1
x2 = 36 + 2 = 38
Q111. The coefficient of x y in 7pqrx is:
1. 7pqr
2. pqr
3. -7pqr
4. 7
Ans: 1. 7pqr
Q112. Which of the following is the numerical coefficient of x y ?
1. 0
2. 1
3. x
4. y
Ans: 2. 1
Solution:
So, if is asked that the numerical coefficient of 5x then the answer will be 5.
the numerical coefficient is the number, which is before any constant like x, y, z. etc. and we know if we multiply any number or
variable with 1 it remains same.
Here there is no number before (x y ) so we assume it as 1.
Hence the answer is 1.
Q113. Like term as 4m n is:
1. 4m n
2. -6m n
3. 6pm n
4. 4m n
Ans: 2. -6m n
Solution:
We knoe that, the like terms contain the same literal factor. so, the like as 4m n , -6m n , as it contains the same literal factor m n .
Q114. The number of like terms in
1
4 a2bc, −
2
3 bca2,
2
5 ba2c −
1
2 cba2 is:
1. 4
2. 3
3. 6
4. 2
Ans: 1. 4
Solution:
All are like terms.
Q115. The coefficient of xy 2z in -7x 2y 3z is:
1. 7xy
2. 7xy
3. -xy
4. xy
Ans: 1. 7xy
Solution:
-7x y z = (-7xy)(xy z)
Q116. The value of (x + 3) – (x – 3) is:
1. 1 – x
2. 18x + 54
3. 3x – 5
4. 0
Ans: 2. 18x + 54
Q117. The value of (a + b) – (a – b) is:
1. 4ab
2. -4ab
3. 2a + 2b
4. 2a – 2b
Ans: 1. 4ab
Solution:
We have,
(a + b) – (a – b) = a + b + 2ab – (a + b – 2ab)
= a + b + 2ab – a − b + 2ab = a – a + b – b + 2ab + 2ab
= 2ab + 2ab
= 4ab
Q118. Add 9x + 2xy – 3x and 3yx + 2xy – y.
1. 5xy.+x
2. 5yx – x
3. 9x + 5xy – x – y
4. 9x + 5xy + x – y
Ans: 3. 9x + 5xy – x – y
Solution:
9×2 + 2xy − 3x + 3xy + 2x − y
¯
9×2 + 5xy − x − y
Q119. The area of a rectangle whose length and breadth are 9y and 4y respectively is:
1. 4y
2. 9y
3. 36y
4. 13y
Ans: 3. 36y
Solution:
Area = (9y)(4y ) = 36y
Q120. The area of a rectangle whose length and breadth are 3y and 9y respectively is:
1. 21y
2. 27y
3. 12y
4. y
Ans: 2. 27y
Solution:
Area of rectangle = length x breadth = 3y × 9y = 27y
Q121. Tick (✓ ) the correct answer:
(82) – (18) = ?
1. 8218
2. 6418
3. 6400
4. 7204
Ans: 3. 6400
Solution:
(82) – (18)
= (82 + 18)(82 – 18)
= 100 × 64
= 6400
Q122. The number of like terms in 9x , 16x y, – 8x , 12xy , 6x is:
1. 3
2. 2
3. 4
4. 5
Ans: 1. 3
Solution:
9x , – 8x , 6x
Q123. The value of the product 3 +
5
x 9 −
15
x +
25
x2 at x = 1 is:
1. 152
2. 150
3. 148
4. None
Ans: 1. 152
Q124. On dividing p(4p – 16) by 4p(p – 2), we get
1. 2p + 4
2. 2p – 4
3. p + 2
4. p – 2
Ans: 3. p + 2
Solution:
We have,
p ( 4p2 − 16 )
4p ( p − 2 ) =
p [ ( 2p )2 − 42 ]
4p ( p − 2 )
=
( 2p − 4 ) ( 2p + 4 )
4 ( p − 2 )
=
2 ( p − 2 ) .2 ( p + 2 )
4 ( p − 2 )
=
4 ( p − 2 ) ( p + 2 )
4 ( p − 2 )
= p + 2
Q125. The coefficient of x y in -15 x y is:
1. 15
2. -15
3. 3
4. 5
Ans: 2. -15
Q126. The value of 25x + 16y + 40xy at x = 1 and y = -1 is:
1. -48
2. 1
3. 81
4. None
Ans: 2. 1
Q127. Square of 3x – 4y is:
1. 9x – 16y
2. 6x – 8y
3. 9x + 16y + 24xy
4. 9x + 16y – 24xy
Ans: 4. 9x + 16y – 24xy
Solution:
Square of (3x – 4y) will be (3x – 4y)
comparing (3x – 4y) with (a – b)
We get a = 3x and b = 4y
now, using identity, (a – b) = a – 2ab + b
(3x – 4y) = (3x) – 2.3x.4y + (4y)
= 9x + 16y – 24xy
Q128. The Value of
7.83 × 7.83 − 1.17 × 1.17
6.66 is:
1. 9
2. 6.66
3. 1.176
4. None
Ans: 1. 9
Q129. The value of (2x + 4) ÷ 2 is:
1. 2x + 2
2. x + 2
3. x + 4
4. 2x + 4
Ans: 2. x + 2
Solution:
We have,
(2x + 4) ÷ 2
=
2×2 + 4
2
=
2 ( x2 + 4 )
2
= x2 + 2
Q130. The volume of a rectangle with length, breadth and height as 5x, 3x and 7x respectively is:
1. 105x
2. 105x
3. 105x
4. 105x
Ans: 1. 105x
Solution:
Volume of rectangle = Length × breadth × height
V = 5x × 3x × 7x
V = 105x
V = 105x cubic unit.
Q131. The algebraic expression 3x + 2y + 6 is a:
1. Trinomial
2. Monomial
3. Binomial
4. None of the above
Ans: 1. Trinomial
Solution:
The algebraic expression containing three terms is called a trinomial.
Here, 3x, 2y and 6 are three terms.
Q132. The volume of a cube of side 2a is:
1. 4a
2. 2a
3. 8a
4. 8
Ans: 3. 8a
Solution:
Volume = 2a × 2a × 2a = 8a
Q133. The sum of 5x , – 7x , 8x , 11x and -9x is:
1. 2x
2. 4x
3. 6x
4. 8x
Ans: 4. 8x
Solution:
Sum = {5 + (-7) + 8 + 11 + (-9)} x = 8x
Q134. Tick (✓ ) the correct answer:
If (a – b) = 7 and ab = 9, then (a + b ) = ?
1. 67
2. 31
3. 40
4. 58
Ans: 1. 67
Solution:
a – b = 7
ab = 9
a + b = (a – b) + 2ab
= (7) + 2 × 9
= 49 + 18
= 67
Q135. Simplify 4x(5x + 3x) + 2x and find its value for x = 2
1. 20x + 12x + 2x 211
2. 20x + 20x ; 240
3. 20x + 20x ; 120
4. 20x + 12x + 2x ; 212
Ans: 4. 20x + 12x + 2x ; 212
Solution:
Simplifying the given expression, 4x(5x ) + 4x(3x) + 2x = 20x + 12x + 2x
For x = 2, the value of expression = 20(2) + 12(2) + 2(2) = 20 × 8 + 12 × 4 + 4 = 160 + 48 + 4 = 212
Q136. If < a < 1 then the value of a+
1
a is:
1. Greater than 2
2. Grater than 4
3. Less than 4
4. Less than 2
Ans: 1. Greater than 2
Q137. The algebraic expression 3x + 2y + 6 is:
1. monomial
2. Binomial
3. Trinomial
4. None of the above
Ans: 3. Trinomial
Solution:
The algebraic expression containing three terms is called a trinomial.
Here, 3x, 2y and 6 are three terms.
Q138. How many terms are there in the expression 7x + 5x – 5?
1. 1
2. 2
3. 3
4. 5
Ans: 3. 3
Solution:
7x , 5x, – 5
Also Read Notes: –Class 8th Mathematics Chapter 9: Algebraic Expressions and Identities